商务与经济统计习题答案(第8版,中文版)SBE8-SM15


    Chapter 15
    Multiple Regression


    Learning Objectives

    1 Understand how multiple regression analysis can be used to develop relationships involving one dependent variable and several independent variables

    2 Be able to interpret the coefficients in a multiple regression analysis

    3 Know the assumptions necessary to conduct statistical tests involving the hypothesized regression model

    4 Understand the role of computer packages in performing multiple regression analysis

    5 Be able to interpret and use computer output to develop the estimated regression equation

    6 Be able to determine how good a fit is provided by the estimated regression equation

    7 Be able to test for the significance of the regression equation

    8 Understand how multicollinearity affects multiple regression analysis

    9 Know how residual analysis can be used to make a judgement as to the appropriateness of the model identify outliers and determine which observations are influential















    Solutions

    1 a b1 5906 is an estimate of the change in y corresponding to a 1 unit change in x1 when x2 is held constant

    b2 4980 is an estimate of the change in y corresponding to a 1 unit change in x2 when x1 is held constant

    2 a The estimated regression equation is

    4506 + 194x1

    An estimate of y when x1 45 is

    4506 + 194(45) 13236

    b The estimated regression equation is

    8522 + 432x2

    An estimate of y when x2 15 is

    8522 + 432(15) 15002

    c The estimated regression equation is

    1837 + 201x1 + 474x2

    An estimate of y when x1 45 and x2 15 is

    1837 + 201(45) + 474(15) 14318

    3 a b1 38 is an estimate of the change in y corresponding to a 1 unit change in x1 when x2 x3 and x4
    are held constant

    b2 23 is an estimate of the change in y corresponding to a 1 unit change in x2 when x1 x3 and x4 are held constant

    b3 76 is an estimate of the change in y corresponding to a 1 unit change in x3 when x1 x2 and x4 are held constant

    b4 27 is an estimate of the change in y corresponding to a 1 unit change in x4 when x1 x2 and x3 are held constant

    4 a 235 + 10(15) + 8(10) 255 sales estimate 255000

    b Sales can be expected to increase by 10 for every dollar increase in inventory investment when advertising expenditure is held constant Sales can be expected to increase by 8 for every dollar increase in advertising expenditure when inventory investment is held constant



    5 a The Minitab output is shown below

    The regression equation is
    Revenue 886 + 160 TVAdv

    Predictor Coef SE Coef T P
    Constant 88638 1582 5602 0000
    TVAdv 16039 04778 336 0015

    S 1215 RSq 653 RSq(adj) 595

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 16640 16640 1127 0015
    Residual Error 6 8860 1477
    Total 7 25500

    b The Minitab output is shown below

    The regression equation is
    Revenue 832 + 229 TVAdv + 130 NewsAdv

    Predictor Coef SE Coef T P
    Constant 83230 1574 5288 0000
    TVAdv 22902 03041 753 0001
    NewsAdv 13010 03207 406 0010

    S 06426 RSq 919 RSq(adj) 887

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 23435 11718 2838 0002
    Residual Error 5 2065 0413
    Total 7 25500

    Source DF Seq SS
    TVAdv 1 16640
    NewsAdv 1 6795

    c No it is 160 in part 2(a) and 299 above In this exercise it represents the marginal change in revenue due to an increase in television advertising with newspaper advertising held constant

    d Revenue 832 + 229(35) + 130(18) 9356 or 93560

    6 a The Minitab output is shown below

    The regression equation is
    Speed 498 + 00151 Weight

    Predictor Coef SE Coef T P
    Constant 4978 1911 261 0021
    Weight 0015104 0006005 252 0025


    S 7000 RSq 311 RSq(adj) 262

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 30995 30995 633 0025
    Error 14 68600 4900
    Total 15 99595

    b The Minitab output is shown below

    The regression equation is
    Speed 805 000312 Weight + 0105 Horsepwr

    Predictor Coef SE Coef T P
    Constant 80487 9139 881 0000
    Weight 0003122 0003481 090 0386
    Horsepwr 010471 001331 786 0000

    S 3027 RSq 880 RSq(adj) 862

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 87680 43840 4783 0000
    Residual Error 13 11915 917
    Total 15 99595

    7 a The Minitab output is shown below

    The regression equation is
    Sales 665 + 0414 Compet 0270 Heller

    Predictor Coef SE Coef T P
    Constant 6652 4188 159 0156
    Compet 04139 02604 159 0156
    Heller 026978 008091 333 0013

    S 1874 RSq 653 RSq(adj) 554

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 46188 23094 658 0025
    Residual Error 7 24573 3510
    Total 9 70761

    b b1 414 is an estimate of the change in the quantity sold (1000s) of the Heller mower with respect to a 1 change in price in competitor’s mower with the price of the Heller mower held constant b2 270 is an estimate of the change in the quantity sold (1000s) of the Heller mower with respect to a 1 change in its price with the price of the competitor’s mower held constant

    c 665 + 0414(170) 0270(160) 9368 or 93680 units


    8 a The Minitab output is shown below

    The regression equation is
    Return 247 328 Safety + 346 ExpRatio

    Predictor Coef SE Coef T P
    Constant 2474 1104 224 0039
    Safety 3284 1395 235 0031
    ExpRatio 3459 1413 245 0026

    S 1698 RSq 582 RSq(adj) 533

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 68232 34116 1184 0001
    Residual Error 17 48997 2882
    Total 19 117230

    b

    9 a The Minitab output is shown below

    The regression equation is
    College 267 143 Size + 00757 SatScore

    Predictor Coef SE Coef T P
    Constant 2671 5167 052 0613
    Size 14298 09931 144 0170
    SatScore 007574 003906 194 0072

    S 1242 RSq 382 RSq(adj) 300

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 14304 7152 464 0027
    Residual Error 15 23127 1542
    Total 17 37431

    b 267 143(20) + 00757(1000) 738

    Estimate is 738

    10 a The Minitab output is shown below

    The regression equation is
    Revenue 333 + 798 Cars

    Predictor Coef SE Coef T P
    Constant 3334 8308 040 0695
    Cars 79840 06323 1263 0000
    S 2267 RSq 925 RSq(adj) 919


    Analysis of Variance

    Source DF SS MS F P
    Regression 1 8192067 8192067 15944 0000
    Error 13 667936 51380
    Total 14 8860003

    b An increase of 1000 cars in service will result in an increase in revenue of 798 million

    c The Minitab output is shown below

    The regression equation is
    Revenue 106 + 894 Cars 0191 Location

    Predictor Coef SE Coef T P
    Constant 10597 8552 124 0239
    Cars 89427 07746 1155 0000
    Location 01914 01026 187 0087

    S 2077 RSq 942 RSq(adj) 932

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 8342186 4171093 9666 0000
    Error 12 517817 43151
    Total 14 8860003

    11 a SSE SST SSR 6724125 6216375 50775

    b

    c

    d The estimated regression equation provided an excellent fit

    12 a

    b

    c Yes after adjusting for the number of independent variables in the model we see that 905 of the variability in y has been accounted for

    13 a

    b

    c The estimated regression equation provided an excellent fit

    14 a

    b

    c The adjusted coefficient of determination shows that 68 of the variability has been explained by the two independent variables thus we conclude that the model does not explain a large amount of variability

    15 a



    b Multiple regression analysis is preferred since both R2 andshow an increased percentage of the variability of y explained when both independent variables are used

    16 Note the Minitab output is shown with the solution to Exercise 6

    a No RSq 311

    b Multiple regression analysis is preferred since both RSq and RSq(adj) show an increased percentage of the variability of y explained when both independent variables are used

    17 a



    b The fit is not very good

    18 Note The Minitab output is shown with the solution to Exercise 10

    a RSq 942 RSq(adj) 932

    b The fit is very good

    19 a MSR SSRp 62163752 3108188


    b F MSRMSE 310818872536 4285

    F05 474 (2 degrees of freedom numerator and 7 denominator)

    Since F 4285 > F05 474 the overall model is significant

    c t 59060813 726

    t025 2365 (7 degrees of freedom)

    Since t 2365 > t025 2365 b1 is significant

    d t 49800567 878

    Since t 878 > t025 2365 b2 is significant

    20 A portion of the Minitab output is shown below

    The regression equation is
    Y 184 + 201 X1 + 474 X2

    Predictor Coef SE Coef T P
    Constant 1837 1797 102 0341
    X1 20102 02471 813 0000
    X2 47378 09484 500 0002

    S 1271 RSq 926 RSq(adj) 904

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 140522 70261 4350 0000
    Residual Error 7 11307 1615
    Total 9 151829

    a Since the pvalue corresponding to F 4350 is 000 < a 05 we reject H0 b1 b2 0 there is a significant relationship

    b Since the pvalue corresponding to t 813 is 000 < a 05 we reject H0 b1 0 b1 is significant

    c Since the pvalue corresponding to t 500 is 002 < a 05 we reject H0 b2 0 b2 is significant

    21 a In the two independent variable case the coefficient of x1 represents the expected change in y corresponding to a one unit increase in x1 when x2 is held constant In the single independent variable case the coefficient of x1 represents the expected change in y corresponding to a one unit increase in x1

    b Yes If x1 and x2 are correlated one would expect a change in x1 to be accompanied by a change in x2





    22 a SSE SST SSR 16000 12000 4000





    b F MSRMSE 600057143 1050

    F05 474 (2 degrees of freedom numerator and 7 denominator)

    Since F 1050 > F05 474 we reject H0 There is a significant relationship among the variables

    23 a F 2838

    F01 1327 (2 degrees of freedom numerator and 1 denominator)

    Since F > F01 1327 reject H0

    Alternatively the pvalue of 002 leads to the same conclusion

    b t 753

    t025 2571

    Since t > t025 2571 b1 is significant and x1 should not be dropped from the model

    c t 406

    t025 2571

    Since t > t025 2571 b2 is significant and x2 should not be dropped from the model

    24 Note The Minitab output is shown in part (b) of Exercise 6

    a F 4783

    F05 381 (2 degrees of freedom numerator and 13 denominator)

    Since F 4783 > F05 381 we reject H0 b1 b2 0

    Alternatively since the pvalue 000 < a 05 we can reject H0

    b For Weight

    H0 b1 0 Ha b1 ¹ 0

    Since the pvalue 0386 > a 005 we cannot reject H0



    For Horsepower

    H0 b2 0 Ha b2 ¹ 0

    Since the pvalue 0000 < a 005 we can reject H0

    25 a The Minitab output is shown below

    The regression equation is
    PE 604 + 0692 Profit + 0265 Sales

    Predictor Coef SE Coef T P
    Constant 6038 4589 132 0211
    Profit 06916 02133 324 0006
    Sales 02648 01871 142 0180

    S 5456 RSq 472 RSq(adj) 390

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 34528 17264 580 0016
    Residual Error 13 38700 2977
    Total 15 73228

    b Since the pvalue 0016 < a 005 there is a significant relationship among the variables

    c For Profit Since the pvalue 0006 < a 005 Profit is significant

    For Sales Since the pvalue 0180 > a 005 Sales is not significant

    26 Note The Minitab output is shown with the solution to Exercise 10

    a Since the pvalue corresponding to F 9666 is 0000 < a 05 there is a significant relationship among the variables

    b For Cars Since the pvalue 0000 < a 005 Cars is significant

    c For Location Since the pvalue 0087 > a 005 Location is not significant

    27 a 291270 + 5906(180) + 4980(310) 2898150

    b The point estimate for an individual value is 2898150 the same as the point estimate of the mean value

    28 a Using Minitab the 95 confidence interval is 13216 to 15416

    b Using Minitab the 95 prediction interval is 11113 to 17518





    29 a 832 + 229(35) + 130(18) 93555 or 93555

    Note In Exercise 5b the Minitab output also shows that b0 83230 b1 22902
    and b2 13010 hence 83230 + 22902x1 + 13010x2 Using this estimated regression equation we obtain

    83230 + 22902(35) + 13010(18) 93588 or 93588

    The difference (93588 93555 33) is simply due to the fact that additional significant digits are used in the computations From a practical point of view however the difference is not enough to be concerned about In practice a computer software package is always used to perform the computations and this will not be an issue

    The Minitab output is shown below

    Fit StdevFit 95 CI 95 PI
    93588 0291 ( 92840 94335) ( 91774 95401)

    Note that the value of FIT () is 93588

    b Confidence interval estimate 92840 to 94335 or 92840 to 94335

    c Prediction interval estimate 91774 to 95401 or 91774 to 95401

    30 a Since weight is not statistically significant (see Exercise 24) we will use an estimated regression equation which uses only Horsepower to predict the speed at 14 mile The Minitab output is shown below

    The regression equation is
    Speed 726 + 00968 Horsepwr

    Predictor Coef SE Coef T P
    Constant 72650 2655 2736 0000
    Horsepwr 0096756 0009865 981 0000

    S 3006 RSq 873 RSq(adj) 864

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 86943 86943 9621 0000
    Residual Error 14 12652 904
    Total 15 99595

    Unusual Observations
    Obs Horsepwr Speed Fit SE Fit Residual St Resid
    2 290 108000 100709 0814 7291 252R
    6 450 116200 116190 2036 0010 000 X

    R denotes an observation with a large standardized residual
    X denotes an observation whose X value gives it large influence

    The output shows that the point estimate is a speed of 101290 miles per hour

    b The 95 confidence interval is 99490 to 103089 miles per hour

    c The 95 prediction interval is 94596 to 107984 miles per hour

    31 a Using Minitab the 95 confidence interval is 5837 to 7503

    b Using Minitab the 95 prediction interval is 3524 to 9059

    32 a E(y) b0 + b1 x1 + b2 x2 where

    x2 0 if level 1 and 1 if level 2

    b E(y) b0 + b1 x1 + b2(0) b0 + b1 x1

    c E(y) b0 + b1 x1 + b2(1) b0 + b1 x1 + b2

    d b2 E(y | level 2) E(y | level 1)

    b1 is the change in E(y) for a 1 unit change in x1 holding x2 constant

    33 a two

    b E(y) b0 + b1 x1 + b2 x2 + b3 x3 where

    x2
    x3
    Level
    0
    0
    1
    1
    0
    2
    0
    1
    3

    c E(y | level 1) b0 + b1 x1 + b2(0) + b3(0) b0+ b1 x1

    E(y | level 2) b0 + b1 x1 + b2(1) + b3(0) b0 + b1 x1 + b2

    E(y | level 3) b0 + b1 x1 + b2(0) + b3(0) b0 + b1 x1 + b3

    b2 E(y | level 2) E(y | level 1)

    b3 E(y | level 3) E(y | level 1)

    b1 is the change in E(y) for a 1 unit change in x1 holding x2 and x3 constant

    34 a 15300

    b Estimate of sales 101 42(2) + 68(8) + 153(0) 561 or 56100

    c Estimate of sales 101 42(1) + 68(3) + 153(1) 416 or 41600

    35 a Let Type 0 if a mechanical repair
    Type 1 if an electrical repair

    The Minitab output is shown below


    The regression equation is
    Time 345 + 0617 Type

    Predictor Coef SE Coef T P
    Constant 34500 05467 631 0000
    Type 06167 07058 087 0408

    S 1093 RSq 87 RSq(adj) 00

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 0913 0913 076 0408
    Residual Error 8 9563 1195
    Total 9 10476

    b The estimated regression equation did not provide a good fit In fact the pvalue of 408 shows that the relationship is not significant for any reasonable value of a

    c Person 0 if Bob Jones performed the service and Person 1 if Dave Newton performed the service The Minitab output is shown below

    The regression equation is
    Time 462 160 Person

    Predictor Coef SE Coef T P
    Constant 46200 03192 1447 0000
    Person 16000 04514 354 0008

    S 07138 RSq 611 RSq(adj) 562

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 64000 64000 1256 0008
    Residual Error 8 40760 05095
    Total 9 104760

    d We see that 611 of the variability in repair time has been explained by the repair person that performed the service an acceptable but not good fit

    36 a The Minitab output is shown below

    The regression equation is
    Time 186 + 0291 Months + 110 Type 0609 Person

    Predictor Coef SE Coef T P
    Constant 18602 07286 255 0043
    Months 029144 008360 349 0013
    Type 11024 03033 363 0011
    Person 06091 03879 157 0167

    S 04174 RSq 900 RSq(adj) 850



    Analysis of Variance

    Source DF SS MS F P
    Regression 3 94305 31435 1804 0002
    Residual Error 6 10455 01743
    Total 9 104760

    b Since the pvalue corresponding to F 1804 is 002 < a 05 the overall model is statistically significant

    c The pvalue corresponding to t 157 is 167 > a 05 thus the addition of Person is not statistically significant Person is highly correlated with Months (the sample correlation coefficient is 691) thus once the effect of Months has been accounted for Person will not add much to the model

    37 a Let Position 0 if a guard
    Position 1 if an offensive tackle

    b The Minitab output is shown below

    The regression equation is
    Rating 112 + 0732 Position + 00222 Weight 228 Speed

    Predictor Coef SE Coef T P
    Constant 11223 4523 248 0022
    Position 07324 02893 253 0019
    Weight 002219 001039 214 0045
    Speed 22775 09290 245 0023

    S 06936 RSq 475 RSq(adj) 401

    Analysis of Variance

    Source DF SS MS F P
    Regression 3 91562 30521 635 0003
    Residual Error 21 101014 04810
    Total 24 192576

    c Since the pvalue corresponding to F 635 is 003 < a 05 there is a significant relationship between rating and the independent variables

    d The value of RSq (adj) is 401 the estimated regression equation did not provide a very good fit

    e Since the pvalue for Position is t 253 < a 05 position is a significant factor in the player’s rating

    f










    38 a The Minitab output is shown below

    The regression equation is
    Risk 918 + 108 Age + 0252 Pressure + 874 Smoker

    Predictor Coef SE Coef T P
    Constant 9176 1522 603 0000
    Age 10767 01660 649 0000
    Pressure 025181 004523 557 0000
    Smoker 8740 3001 291 0010

    S 5757 RSq 873 RSq(adj) 850

    Analysis of Variance

    Source DF SS MS F P
    Regression 3 36607 12202 3682 0000
    Residual Error 16 5302 331
    Total 19 41909

    b Since the pvalue corresponding to t 291 is 010 < a 05 smoking is a significant factor

    c Using Minitab the point estimate is 3427 the 95 prediction interval is 2135 to 4718 Thus the probability of a stroke (2135 to 4718 at the 95 confidence level) appears to be quite high The physician would probably recommend that Art quit smoking and begin some type of treatment designed to reduce his blood pressure

    39 a The Minitab output is shown below

    The regression equation is
    Y 020 + 260 X

    Predictor Coef SE Coef T P
    Constant 0200 2132 009 0931
    X 26000 06429 404 0027

    S 2033 RSq 845 RSq(adj) 793

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 67600 67600 1635 0027
    Residual Error 3 12400 4133
    Total 4 80000

    b Using Minitab we obtained the following values

    xi

    yi


    Standardized Residual
    1
    3
    28
    16
    2
    7
    54
    94
    3
    5
    80
    165
    4
    11
    106
    24
    5
    14
    132
    62


    The point (35) does not appear to follow the trend of remaining data however the value of the standardized residual for this point 165 is not large enough for us to conclude that (3 5) is an outlier

    c Using Minitab we obtained the following values


    xi

    yi
    Studentized
    Deleted Residual
    1
    3
    13
    2
    7
    91
    3
    5
    442
    4
    11
    19
    5
    14
    54

    t025 4303 (n p 2 5 1 2 2 degrees of freedom)

    Since the studentized deleted residual for (3 5) is 442 < 4303 we conclude that the 3rd observation is an outlier

    40 a The Minitab output is shown below

    The regression equation is
    Y 533 + 311 X

    Predicator
    Coef
    Stdev
    tratio
    p
    Constant
    53280
    5786
    921
    0003
    X
    31100
    02016
    1543
    0001

    s 2851 Rsq 988 Rsq (adj) 983
    Analysis of Variance

    SOURCE
    DF
    SS
    MS
    F
    p
    Regression
    1
    19344
    19344
    23803
    0001
    Error
    3
    244
    81


    Total
    4
    15988




    b Using the Minitab we obtained the following values

    xi

    yi
    Studentized
    Deleted Residual
    22
    12
    194
    24
    21
    12
    26
    31
    179
    28
    35
    40
    40
    70
    190

    t025 4303 (n p 2 5 1 2 2 degrees of freedom)

    Since none of the studentized deleted residuals are less than 4303 or greater than 4303 none of the observations can be classified as an outlier





    c Using Minitab we obtained the following values

    xi
    yi
    hi
    22
    12
    38
    24
    21
    28
    26
    31
    22
    28
    35
    20
    40
    70
    92

    The critical value is



    Since none of the values exceed 12 we conclude that there are no influential observations in the data

    d Using Minitab we obtained the following values

    xi
    yi
    Di
    22
    12
    60
    24
    21
    00
    26
    31
    26
    28
    35
    03
    40
    70
    1109

    Since D5 1109 > 1 (rule of thumb critical value) we conclude that the fifth observation is influential

    41 a The Minitab output appears in the solution to part (b) of Exercise 5 the estimated regression equation is

    Revenue 832 + 229 TVAdv + 130 NewsAdv

    b Using Minitab we obtained the following values



    Standardized Residual
    9663
    162
    9041
    108
    9434
    122
    9221
    37
    9439
    110
    9424
    40
    9442
    112
    9335
    108

    With the relatively few observations it is difficult to determine if any of the assumptions regarding the error term have been violated For instance an argument could be made that there does not appear to be any pattern in the plot alternatively an argument could be made that there is a curvilinear pattern in the plot


    c The values of the standardized residuals are greater than 2 and less than +2 thus using test there are no outliers As a further check for outliers we used Minitab to compute the following studentized deleted residuals


    Observation
    Studentized Deleted Residual
    1
    211
    2
    110
    3
    131
    4
    33
    5
    113
    6
    36
    7
    116
    8
    110

    t025 2776 (n p 2 8 2 2 4 degrees of freedom)

    Since none of the studentized deleted residuals is less tan 2776 or greater than 2776 we conclude that there are no outliers in the data

    d Using Minitab we obtained the following values

    Observation
    hi
    Di
    1
    63
    152
    2
    65
    70
    3
    30
    22
    4
    23
    01
    5
    26
    14
    6
    14
    01
    7
    66
    81
    8
    13
    06

    The critical average value is



    Since none of the values exceed 1125 we conclude that there are no influential observations
    However using Cook’s distance measure we see that D1 > 1 (rule of thumb critical value) thus we conclude the first observation is influential Final Conclusion observations 1 is an influential observation

    42 a The Minitab output is shown below

    The regression equation is
    Speed 713 + 0107 Price + 00845 Horsepwr

    Predictor Coef SE Coef T P
    Constant 71328 2248 3173 0000
    Price 010719 003918 274 0017
    Horsepwr 0084496 0009306 908 0000

    S 2485 RSq 919 RSq(adj) 907

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 91566 45783 7412 0000
    Residual Error 13 8030 618
    Total 15 99595

    Source DF Seq SS
    Price 1 40639
    Horsepwr 1 50927

    Unusual Observations
    Obs Price Speed Fit SE Fit Residual St Resid
    2 938 108000 105882 2007 2118 145 X

    X denotes an observation whose X value gives it large influence

    b The standardized residual plot is shown below There appears to be a very unusual trend in the standardized residuals


    xx x
    12+
    x
    SRES1 x
    x
    x
    00+ x x
    x
    x x x


    12+ x

    x
    x

    +++++FITS1
    900 960 1020 1080 1140

    c The Minitab output shown in part (a) did not identify any observations with a large standardized residual thus there does not appear to be any outliers in the data

    d The Minitab output shown in part (a) identifies observation 2 as an influential observation

    43 a The Minitab output is shown below

    The regression equation is
    College 266 + 00970 SatScore

    Predictor Coef SE Coef T P
    Constant 2661 3722 072 0485
    SatScore 009703 003734 260 0019

    S 1283 RSq 297 RSq(adj) 253
    Analysis of Variance

    Source DF SS MS F P
    Regression 1 11108 11108 675 0019
    Residual Error 16 26323 1645
    Total 17 37431

    Unusual Observations
    Obs SatScore College Fit SE Fit Residual St Resid
    3 716 4000 4286 1079 286 041 X

    X denotes an observation whose X value gives it large influence

    b The Minitab output shown in part a identifies observation 3 as an influential observation

    c The Minitab output appears in the solution to Exercise 9 the estimates regression equation is College 267 143 Size + 00757 SATScore

    d The following Minitab output was also provided as part of the regression output for part c

    Unusual Observations

    Obs Size College Fit StdevFit Residual StResid
    3 300 400 3804 1097 196 034 X

    X denotes an obs whose X value gives it large influence

    Observation 3 is still identified as an influential observation

    44 a The expected increase in final college grade point average corresponding to a one point increase in high school grade point average is 0235 when SAT mathematics score does not change Similarly the expected increase in final college grade point average corresponding to a one point increase in the SAT mathematics score is 00486 when the high school grade point average does not change

    b 141 + 0235(84) + 00486(540) 319

    45 a Job satisfaction can be expected to decrease by 869 units with a one unit increase in length of service if the wage rate does not change A dollar increase in the wage rate is associated with a 135 point increase in the job satisfaction score when the length of service does not change

    b 144 869(4) + 135(65) 6739

    46 a The computer output with the missing values filled in is as follows

    The regression equation is

    Y 8103 + 7602 X1 + 3111 X2

    Predicator
    Coef
    Stdev
    tratio

    Constant
    8103
    2667
    304

    X1
    7602
    2105
    361

    X2
    3111
    0613
    508


    s 335 Rsq 923 Rsq (adj) 910
    Analysis of Variance

    SOURCE
    DF
    SS
    MS
    F
    Regression
    2
    1612
    806
    7182
    Error
    12
    13467
    112225

    Total
    14
    174667



    b t025 2179 (12 DF)

    for b1 361 > 2179 reject H0 b1 0

    for b2 508 > 2179 reject H0 b2 0

    c See computer output

    d

    47 a The regression equation is

    Y 141 + 0235 X1 + 00486 X2

    Predictor
    Coef
    Stdev
    tratio
    Constant
    14053
    04848
    290
    X1
    0023467
    0008666
    271
    X2
    00486
    0001077
    451

    s 01298 Rsq 937 Rsq (adj) 919

    Analysis of Variance

    SOURCE
    DF
    SS
    MS
    F
    Regression
    2
    176209
    881
    5244
    Error
    7
    1179
    0168

    Total
    9
    188000



    b F05 474 (2 DF numerator 7 DF denominator)

    F 5244 > F05 significant relationship

    c



    good fit

    d t025 2365 (7 DF)

    for B1 t 271 > 2365 reject H0 B1 0

    for B2 t 451 > 2365 reject H0 B2 0
    48 a The regression equation is

    Y 144 869 X1 + 1352 X2

    Predictor
    Coef
    Stdev
    tratio
    Constant
    14448
    8191
    176
    X1
    869
    1555
    559
    X2
    13517
    2085
    648

    s 3773 Rsq 901 Rsq (adj) 861

    Analysis of Variance

    SOURCE
    DF
    SS
    MS
    F
    Regression
    2
    64883
    324415
    2279
    Error
    5
    7117
    14234

    Total
    7
    72000



    b F05 579 (5 DF)

    F 2279 > F05 significant relationship

    c



    good fit

    d t025 2571 (5 DF)

    for b1 t 559 < 2571 reject H0 b1 0

    for b2 t 648 > 2571 reject H0 b2 0

    49 a The Minitab output is shown below

    The regression equation is
    Price 128 + 226 BookVal

    Predictor Coef SE Coef T P
    Constant 12793 6624 193 0064
    BookVal 22649 06631 342 0002

    S 1950 RSq 294 RSq(adj) 269

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 44339 44339 1167 0002
    Error 28 106423 3801
    Total 29 150761
    b The value of Rsq is 294 the estimated regression equation does not provide a good fit

    c The Minitab output is shown below

    The regression equation is
    Price 588 + 254 BookVal + 0484 ReturnEq

    Predictor Coef SE Coef T P
    Constant 5877 5545 106 0299
    BookVal 25356 05331 476 0000
    ReturnEq 04841 01174 412 0000

    S 1555 RSq 567 RSq(adj) 535

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 85442 42721 1766 0000
    Error 27 65319 2419
    Total 29 150761

    Since the pvalue corresponding to the F test is 0000 the relationship is significant

    50 a The Minitab output is shown below

    The regression equation is
    Speed 976 + 00693 Price 000082 Weight + 00590
    Horsepwr 248 Zero60

    Predictor Coef SE Coef T P
    Constant 9757 1179 827 0000
    Price 006928 003805 182 0096
    Weight 0000816 0002593 031 0759
    Horsepwr 005901 001543 382 0003
    Zero60 24836 09601 259 0025

    S 2127 RSq 950 RSq(adj) 932

    Analysis of Variance

    Source DF SS MS F P
    Regression 4 94618 23655 5228 0000
    Residual Error 11 4977 452
    Total 15 99595

    b Since the pvalue corresponding to the F test is 0000 the relationship is significant

    c Since the pvalues corresponding to the t test for both Horsepwr (pvalue 003) and Zero60 (pvalue 025) are less than 05 both of these independent variables are significant






    d The Minitab output is shown below

    The regression equation is
    Speed 103 + 00558 Horsepwr 319 Zero60

    Predictor Coef SE Coef T P
    Constant 103103 9448 1091 0000
    Horsepwr 005582 001452 384 0002
    Zero60 31876 09658 330 0006

    S 2301 RSq 931 RSq(adj) 920

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 92712 46356 8754 0000
    Residual Error 13 6884 530
    Total 15 99595

    Source DF Seq SS
    Horsepwr 1 86943
    Zero60 1 5768

    Unusual Observations
    Obs Horsepwr Speed Fit SE Fit Residual St Resid
    2 290 108000 103352 1015 4648 225R
    12 155 84600 82747 1773 1853 126 X

    R denotes an observation with a large standardized residual
    X denotes an observation whose X value gives it large influence

    e The standardized residual plot is shown below


    SRES x


    15+
    x x


    2 x x
    00+ x x 2
    x

    xx

    15+
    x x

    ++++++FIT
    840 900 960 1020 1080 1140

    There is an unusual trend in the plot and one observation appears to be an outlier

    f The Minitab output indicates that observation 2 is an outlier

    g The Minitab output indicates that observation 12 is an influential observation

    51 a The Minitab output is shown below

    640+
    x
    Exposure


    480+
    x


    x
    320+



    x
    160+ x 3 x
    x
    ++++++TimesAir
    15 30 45 60 75 90

    b The Minitab output is shown below

    The regression equation is
    Exposure 532 + 674 TimesAir

    Predictor Coef SE Coef T P
    Constant 5324 1653 322 0012
    TimesAir 67427 04472 1508 0000

    S 3170 RSq 966 RSq(adj) 962

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 228520 228520 22736 0000
    Error 8 8041 1005
    Total 9 236561

    Since the pvalue is 0000 the relationship is significant

    c The Minitab output is shown below

    The regression equation is
    Exposure 731 + 504 TimesAir + 101 BigAds



    Predictor Coef SE Coef T P
    Constant 73063 7507 973 0000
    TimesAir 50368 03268 1541 0000
    BigAds 10111 1599 632 0000

    S 1308 RSq 995 RSq(adj) 993

    Analysis of Variance

    Source DF SS MS F P
    Regression 2 235363 117682 68784 0000
    Error 7 1198 171
    Total 9 236561

    d The pvalue corresponding to the t test for BigAds is 0000 thus the dummy variable is significant

    e The dummy variable enables us to fit two different lines to the data this approach is referred to as piecewise linear approximation

    52 a The Minitab output is shown below

    Resale 388 +0000766 Price

    Predictor Coef SE Coef T P
    Constant 38772 4348 892 0000
    Price 00007656 00001900 403 0000

    S 5421 RSq 367 RSq(adj) 344

    Analysis of Variance

    Source DF SS MS F P
    Regression 1 47725 47725 1624 0000
    Residual Error 28 82292 2939
    Total 29 130017

    Since the pvalue corresponding to F 1624 is 000 < a 05 there is a significant relationship between Resale and Price

    b RSq 367 not a very good fit

    c Let Type1 0 and Type2 0 if a small pickup Type1 1 and Type2 0 if a fullsize pickup and Type1 0 and Type2 1 if a sport utility

    The Minitab output using Type1 Type2 and Price is shown below

    The regression equation is
    Resale 426 + 909 Type1 + 792 Type2 +0000341 Price

    Predictor Coef SE Coef T P
    Constant 42554 3562 1195 0000
    Type1 9090 2248 404 0000
    Type2 7917 2163 366 0001
    Price 00003415 00001800 190 0069

    S 4298 RSq 631 RSq(adj) 588

    Analysis of Variance

    Source DF SS MS F P
    Regression 3 81977 27326 1479 0000
    Residual Error 26 48040 1848
    Total 29 130017

    d Since the pvalue corresponding to F 1479 is 000 < a 05 there is a significant relationship between Resale and the independent variables Note that individually Price is not significant at the 05 level of significance If we rerun the regression using just Type1 and Type2 the value of RSq (adj) decreases to 544 a drop of only 4 Thus it appears that for these data the type of vehicle is the strongest predictor of the resale value

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